512n^2-648=0

Solution for 512n^2-648=0 equation:

512n^2-648=0

a = 512; b = 0; c = -648;
Δ = b2-4ac
Δ = 02-4·512·(-648)
Δ = 1327104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1327104}=1152$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1152}{2*512}=\frac{-1152}{1024}
=-1+1/8
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1152}{2*512}=\frac{1152}{1024}
=1+1/8
$